What is the integral from 0 to 3 of (x-5)^3 ?

The integral from 0 to 3 of (x-5)^3 is -609/4

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integral from 0 to 3 of (x-5)^3

\int_{0}^{3} (x - 5)^{3} d x

- \frac{609}{4}

Decimal Notation

- 152.25

Solution steps

\int_{0}^{3} (x - 5)^{3} d x

Apply u-substitution

: \int_{- 5}^{- 2} u^{3} d u

= \int_{- 5}^{- 2} u^{3} d u

Apply the Power Rule

: [\frac{u ^{4}}{4}]_{- 5}^{- 2}

= [\frac{u ^{4}}{4}]_{- 5}^{- 2}

Compute the boundaries:

- \frac{609}{4}

= - \frac{609}{4}

\int_{- 2}^{2} 9 - x^{2} d x

\int_{0.5}^{0.9} 0.0014400000000 \dots x d x

\int_{0}^{3} x^{2} - 6 x + 10 d x

\int_{0}^{2} (x - 3 x^{2})^{3} d x

\int_{0}^{3 π} x sin (x) d x

What is the integral from 0 to 3 of (x-5)^3 ?
The integral from 0 to 3 of (x-5)^3 is -609/4