What is the integral from 1 to 3 of (3x^2) ?

The integral from 1 to 3 of (3x^2) is 26

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 3 of (3x^2)

\int_{1}^{3} (3 x^{2}) d x

26

Solution steps

\int_{1}^{3} 3 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{3} x^{2} d x

Apply the Power Rule

: [\frac{x ^{3}}{3}]_{1}^{3}

= 3 [\frac{x ^{3}}{3}]_{1}^{3}

Compute the boundaries:

\frac{26}{3}

= 3 \cdot \frac{26}{3}

Simplify

= 26

\int_{0}^{2} (x^{2} + 3 x y + 2 y^{2}) d y

\int_{0}^{1} (1 + 2 x + x^{2})^{2} d x

\int_{π}^{3 π} sin (x) d x

\int_{1}^{2} \frac{1}{( 4 - x ) ^{3}} d x

\int_{1}^{4} x e^{- 2 x^{2}} + 6 x - 2 d x

What is the integral from 1 to 3 of (3x^2) ?
The integral from 1 to 3 of (3x^2) is 26