What is the integral from 1 to 2 of (x+e^{-y}) ?

The integral from 1 to 2 of (x+e^{-y}) is e^{-y}+3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 2 of (x+e^{-y})

\int_{1}^{2} (x + e^{- y}) d x

e^{- y} + \frac{3}{2}

Solution steps

\int_{1}^{2} x + e^{- y} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} e^{- y} d x + \int_{1}^{2} x d x

\int_{1}^{2} e^{- y} d x = e^{- y}

\int_{1}^{2} x d x = \frac{3}{2}

= e^{- y} + \frac{3}{2}

\int_{10}^{7} g (x) d x

\int_{1}^{2} (2 x + \frac{3}{x})^{2} d x

\int_{0}^{0.9} e^{- x} d x

\int_{0}^{2 x} (2 x y^{3} - x) d y

\int_{- 1}^{5} (4 x^{3} - 3 x^{2} + 1) d x

What is the integral from 1 to 2 of (x+e^{-y}) ?
The integral from 1 to 2 of (x+e^{-y}) is e^{-y}+3/2