What is the integral from 0 to 1 of 10x^2e^x ?

The integral from 0 to 1 of 10x^2e^x is 10(e-2)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 1 of 10x^2e^x

\int_{0}^{1} 10 x^{2} e^{x} d x

10 (e - 2)

Decimal Notation

7.18281 \dots

Solution steps

\int_{0}^{1} 10 x^{2} e^{x} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 10 \cdot \int_{0}^{1} x^{2} e^{x} d x

Apply Integration By Parts

: [x^{2} e^{x} - \int 2 x e^{x} d x]_{0}^{1}

= 10 [x^{2} e^{x} - \int 2 x e^{x} d x]_{0}^{1}

\int 2 x e^{x} d x = 2 (e^{x} x - e^{x})

= 10 [x^{2} e^{x} - 2 (e^{x} x - e^{x})]_{0}^{1}

Compute the boundaries:

e - 2

= 10 (e - 2)

\int_{0}^{x} k x d x

\int_{0}^{π} x cos (2 x^{2}) d x

\int_{1}^{3} - x^{2} + x d x

\int_{0}^{π} cos (x) x d x

\int_{π}^{0} cos (x) d x

What is the integral from 0 to 1 of 10x^2e^x ?
The integral from 0 to 1 of 10x^2e^x is 10(e-2)