What is the integral from 0 to 2pi of s^2 ?

The integral from 0 to 2pi of s^2 is (8pi^3)/3

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integral from 0 to 2pi of s^2

\int_{0}^{2 π} s^{2} d s

\frac{8 π ^{3}}{3}

Decimal Notation

82.68340 \dots

Solution steps

\int_{0}^{2 π} s^{2} d s

Apply the Power Rule

: [\frac{s ^{3}}{3}]_{0}^{2 π}

= [\frac{s ^{3}}{3}]_{0}^{2 π}

Compute the boundaries:

\frac{8 π ^{3}}{3}

= \frac{8 π ^{3}}{3}

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What is the integral from 0 to 2pi of s^2 ?
The integral from 0 to 2pi of s^2 is (8pi^3)/3