What is the integral from-1 to infinity of 9/(x^2) ?

The integral from-1 to infinity of 9/(x^2) is diverges

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integral from-1 to infinity of 9/(x^2)

\int_{- 1}^{\infty} \frac{9}{x ^{2}} d x

diverges

Solution steps

\int_{- 1}^{\infty} \frac{9}{x ^{2}} d x

Adjust integral based on undefined pointsThere is an undefined point within the boundaries at

: 0

= \int_{- 1}^{0} \frac{9}{x ^{2}} d x + \int_{0}^{\infty} \frac{9}{x ^{2}} d x

\int_{- 1}^{0} \frac{9}{x ^{2}} d x =

diverges

= diverges

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What is the integral from-1 to infinity of 9/(x^2) ?
The integral from-1 to infinity of 9/(x^2) is diverges