What is the integral from 0 to 5.4 of 378-17t^2 ?

The integral from 0 to 5.4 of 378-17t^2 is 1148.904

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integral from 0 to 5.4 of 378-17t^2

\int_{0}^{5.4} 378 - 17 t^{2} d t

1148.904

Solution steps

\int_{0}^{5.4} 378 - 17 t^{2} d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{5.4} 378 d t - \int_{0}^{5.4} 17 t^{2} d t

\int_{0}^{5.4} 378 d t = 2041.2

\int_{0}^{5.4} 17 t^{2} d t = 892.296

= 2041.2 - 892.296

Simplify

= 1148.904

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What is the integral from 0 to 5.4 of 378-17t^2 ?
The integral from 0 to 5.4 of 378-17t^2 is 1148.904