What is the integral from-2 to 1 of x^2-(2-x) ?

The integral from-2 to 1 of x^2-(2-x) is -9/2

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integral from-2 to 1 of x^2-(2-x)

\int_{- 2}^{1} x^{2} - (2 - x) d x

- \frac{9}{2}

Decimal Notation

- 4.5

Solution steps

\int_{- 2}^{1} x^{2} - (2 - x) d x

Simplify

= \int_{- 2}^{1} x^{2} - 2 + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 2}^{1} x^{2} d x - \int_{- 2}^{1} 2 d x + \int_{- 2}^{1} x d x

\int_{- 2}^{1} x^{2} d x = 3

\int_{- 2}^{1} 2 d x = 6

\int_{- 2}^{1} x d x = - \frac{3}{2}

= 3 - 6 - \frac{3}{2}

Simplify

3 - 6 - \frac{3}{2} : - \frac{9}{2}

= - \frac{9}{2}

\int_{0}^{5} y d y

\int_{- 4}^{\infty} \frac{1}{x + 6} d x

\int_{0}^{1} \frac{1}{1 - cos ( x )} d x

\int_{- 3}^{5} \frac{1}{( x - 2 ) ^{3}} d x

What is the integral from-2 to 1 of x^2-(2-x) ?
The integral from-2 to 1 of x^2-(2-x) is -9/2