What is the integral from-1 to 1 of sec^2(x) ?

The integral from-1 to 1 of sec^2(x) is 2tan(1)

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integral from-1 to 1 of sec^2(x)

\int_{- 1}^{1} sec^{2} (x) d x

2 tan (1)

Decimal Notation

3.11481 \dots

Solution steps

\int_{- 1}^{1} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{- 1}^{1}

Compute the boundaries:

2 tan (1)

= 2 tan (1)

\int_{- 1}^{1} 1 + x^{3} d x

\int_{0}^{2} x^{2} - 3 x d x

\int_{0}^{4} (2 x + 1)^{- \frac{1}{2}} d x

\int_{- 2}^{2} 1 - 4 - x^{2} d x

\int_{100}^{200} \frac{600}{x ^{2}} d x

What is the integral from-1 to 1 of sec^2(x) ?
The integral from-1 to 1 of sec^2(x) is 2tan(1)