What is the integral from 0 to pi/4 of 4cos(2x) ?

The integral from 0 to pi/4 of 4cos(2x) is 2

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integral from 0 to pi/4 of 4cos(2x)

\int_{0}^{\frac{π}{4}} 4 cos (2 x) d x

2

Solution steps

\int_{0}^{\frac{π}{4}} 4 cos (2 x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \int_{0}^{\frac{π}{4}} cos (2 x) d x

Apply u-substitution

: \int_{0}^{\frac{π}{2}} cos (u) \frac{1}{2} d u

= 4 \cdot \int_{0}^{\frac{π}{2}} cos (u) \frac{1}{2} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 4 \cdot \frac{1}{2} \cdot \int_{0}^{\frac{π}{2}} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 4 \cdot \frac{1}{2} [sin (u)]_{0}^{\frac{π}{2}}

Simplify

4 \cdot \frac{1}{2} [sin (u)]_{0}^{\frac{π}{2}} : 2 [sin (u)]_{0}^{\frac{π}{2}}

= 2 [sin (u)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= 2 \cdot 1

Simplify

= 2

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What is the integral from 0 to pi/4 of 4cos(2x) ?
The integral from 0 to pi/4 of 4cos(2x) is 2