What is the integral from 1 to infinity of e^{-5n} ?

The integral from 1 to infinity of e^{-5n} is diverges

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integral from 1 to infinity of e^{-5n}

\int_{1}^{\infty} e^{- 5 n}

diverges

Solution steps

\int_{1}^{\infty} e^{- 5 n} d x

Compute the indefinite integral:

\int e^{- 5 n} d x = e^{- 5 n} x + C

Compute the boundaries:

\int_{1}^{\infty} e^{- 5 n} d x =

diverges

= diverges

\int_{0.5}^{1.5} 0.5 x d x

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What is the integral from 1 to infinity of e^{-5n} ?
The integral from 1 to infinity of e^{-5n} is diverges