What is the integral from 8 to 15 of 1/((x-8)^7) ?

The integral from 8 to 15 of 1/((x-8)^7) is diverges

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integral from 8 to 15 of 1/((x-8)^7)

\int_{8}^{15} \frac{1}{( x - 8 ) ^{7}} d x

diverges

Solution steps

\int_{8}^{15} \frac{1}{( x - 8 ) ^{7}} d x

Apply u-substitution

: \int_{0}^{7} \frac{1}{u ^{7}} d u

= \int_{0}^{7} \frac{1}{u ^{7}} d u

Apply the Power Rule

: [- \frac{1}{6 u ^{6}}]_{0}^{7}

= [- \frac{1}{6 u ^{6}}]_{0}^{7}

Compute the boundaries:

diverges

= diverges

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What is the integral from 8 to 15 of 1/((x-8)^7) ?
The integral from 8 to 15 of 1/((x-8)^7) is diverges