What is the derivative of (2^{x+1}-3.5^x^3) ?

The derivative of (2^{x+1}-3.5^x^3) is 3(2^{x+1}-3.5^x)^2(0.69314…*2^{x+1}-1.25276…*3.5^x)

What is the first derivative of (2^{x+1}-3.5^x^3) ?

The first derivative of (2^{x+1}-3.5^x^3) is 3(2^{x+1}-3.5^x)^2(0.69314…*2^{x+1}-1.25276…*3.5^x)

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\frac{d}{d x} ((2^{x + 1} - 3. 5^{x})^{3})

3 (2^{x + 1} - 3. 5^{x})^{2} (0.69314 \dots \cdot 2^{x + 1} - 1.25276 \dots \cdot 3. 5^{x})

Solution steps

\frac{d}{d x} ((2^{x + 1} - 3. 5^{x})^{3})

Apply the chain rule:

3 (2^{x + 1} - 3. 5^{x})^{2} \frac{d}{d x} (2^{x + 1} - 3. 5^{x})

= 3 (2^{x + 1} - 3. 5^{x})^{2} \frac{d}{d x} (2^{x + 1} - 3. 5^{x})

\frac{d}{d x} (2^{x + 1} - 3. 5^{x}) = 0.69314 \dots \cdot 2^{x + 1} - 1.25276 \dots \cdot 3. 5^{x}

= 3 (2^{x + 1} - 3. 5^{x})^{2} (0.69314 \dots \cdot 2^{x + 1} - 1.25276 \dots \cdot 3. 5^{x})

\frac{d ^{3}}{d x ^{3}} (1 + x^{2})

\int 5 x + sin (x) d x

x \to - 4 lim (x + 4)

(y + 4) (\frac{d y}{d x}) = 2 x y + 4 y

\frac{d y}{d x} = 4 x e^{2 y}

What is the derivative of (2^{x+1}-3.5^x^3) ?
The derivative of (2^{x+1}-3.5^x^3) is 3(2^{x+1}-3.5^x)^2(0.69314…*2^{x+1}-1.25276…*3.5^x)
What is the first derivative of (2^{x+1}-3.5^x^3) ?
The first derivative of (2^{x+1}-3.5^x^3) is 3(2^{x+1}-3.5^x)^2(0.69314…*2^{x+1}-1.25276…*3.5^x)