What is the integral from 0 to 1 of sin(pi)y ?

The integral from 0 to 1 of sin(pi)y is 0

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integral from 0 to 1 of sin(pi)y

\int_{0}^{1} sin (π) y d y

0

Solution steps

\int_{0}^{1} sin (π) y d y

sin (π) y = 0

= \int_{0}^{1} 0 d y

Integral of a constant:

\int a d x = a x

= [0 \cdot y]_{0}^{1}

Simplify

= [0]_{0}^{1}

Compute the boundaries:

0

= 0

\int_{2}^{5} x^{2} - 4 x + 5 d x

\int_{0}^{\infty} \frac{1}{4 x + 3} d x

\int_{4}^{16} 2 x - 1 d x

\int_{0}^{x} x^{3} y^{2} d y

\int_{- 2}^{0} 2 x + 4 d x

What is the integral from 0 to 1 of sin(pi)y ?
The integral from 0 to 1 of sin(pi)y is 0