What is the tangent of f(x)=tan(x)+x,\at x= pi/4 ?

The tangent of f(x)=tan(x)+x,\at x= pi/4 is y=3x+1-pi/2

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tangent of f(x)=tan(x)+x,\at x= pi/4

tangent of

f (x) = tan (x) + x, at x = \frac{π}{4}

y = 3 x + 1 - \frac{π}{2}

Solution steps

Find the tangent point:

(\frac{π}{4}, 1 + \frac{π}{4})

Find the slope of

f (x) = tan (x) + x : \frac{df ( x )}{d x} = sec^{2} (x) + 1

Compute the slope of

f (x) = tan (x) + x

x = \frac{π}{4} : m = 3

Find the line with slope m=

3

and passing through

(\frac{π}{4}, 1 + \frac{π}{4}) : y = 3 x + 1 - \frac{π}{2}

y = 3 x + 1 - \frac{π}{2}

x \to - 2 lim (- 6)

\frac{d}{d x} (\frac{x ^{3}}{( x + 1 ) ^{2}})

\int 3 x x + 3 d x

\frac{\partial}{\partial v} (sin^{2} (u))

\frac{d}{d x} ((2 x - 3)^{4} (x^{2} + x + 1)^{5})

What is the tangent of f(x)=tan(x)+x,\at x= pi/4 ?
The tangent of f(x)=tan(x)+x,\at x= pi/4 is y=3x+1-pi/2