What is the integral from 1 to 2 of (Inx)/x ?

The integral from 1 to 2 of (Inx)/x is In

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integral from 1 to 2 of (Inx)/x

\int_{1}^{2} \frac{I n x}{x} d x

I n

Solution steps

\int_{1}^{2} \frac{I n x}{x} d x

Cancel the common factor:

x

= \int_{1}^{2} I n d x

Integral of a constant:

\int a d x = a x

= [I n x]_{1}^{2}

Compute the boundaries:

I n

= I n

\int_{0}^{π} e^{\frac{x}{2}} cos (x) d x

\int_{1}^{2} 18 x + 37 d x

\int_{- 2}^{2} x^{4} - 4 x^{2} d x

\int_{- 3}^{x} \frac{1}{3} (1 + \frac{x}{3}) d x

\int_{\frac{π}{4}}^{\frac{π}{2}} 2 x - sin (2 x) d x

What is the integral from 1 to 2 of (Inx)/x ?
The integral from 1 to 2 of (Inx)/x is In