What is the integral from-6 to infinity of 1/(x+8) ?

The integral from-6 to infinity of 1/(x+8) is diverges

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integral from-6 to infinity of 1/(x+8)

\int_{- 6}^{\infty} \frac{1}{x + 8} d x

diverges

Solution steps

\int_{- 6}^{\infty} \frac{1}{x + 8} d x

Compute the indefinite integral:

\int \frac{1}{x + 8} d x = ln ∣ x + 8 ∣ + C

Compute the boundaries:

\int_{- 6}^{\infty} \frac{1}{x + 8} d x =

diverges

= diverges

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What is the integral from-6 to infinity of 1/(x+8) ?
The integral from-6 to infinity of 1/(x+8) is diverges