What is the integral from 0 to 5 of 1/(x^4) ?

The integral from 0 to 5 of 1/(x^4) is diverges

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integral from 0 to 5 of 1/(x^4)

\int_{0}^{5} \frac{1}{x ^{4}} d x

diverges

Solution steps

\int_{0}^{5} \frac{1}{x ^{4}} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{0}^{5}

= [- \frac{1}{3 x ^{3}}]_{0}^{5}

Compute the boundaries:

diverges

= diverges

\int_{0}^{\frac{π}{12}} sin^{2} (3 x) d x

\int_{1}^{2} 5 x^{3} - 2 x d x

\int_{- 3}^{2} x + 1 d x

\int_{0}^{a} a x - x^{2} d x

\int_{- 3}^{0} 18 x + 55 d x

What is the integral from 0 to 5 of 1/(x^4) ?
The integral from 0 to 5 of 1/(x^4) is diverges