What is the integral from 0 to 5 of 1/(x^{0.5)} ?

The integral from 0 to 5 of 1/(x^{0.5)} is 2sqrt(5)

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integral from 0 to 5 of 1/(x^{0.5)}

\int_{0}^{5} \frac{1}{x ^{0.5}} d x

25

Decimal Notation

4.47213 \dots

Solution steps

\int_{0}^{5} \frac{1}{x ^{0.5}} d x

Apply the Power Rule

: [2 x^{0.5}]_{0}^{5}

= [2 x^{0.5}]_{0}^{5}

Apply radical rule:

= [2 x]_{0}^{5}

Compute the boundaries:

25

= 25

\int_{- 3}^{1} 3 t^{3} + 2 t^{2} d t

\int_{0}^{\frac{π}{15}} x tan^{2} (5 x) d x

\int_{\frac{π}{2}}^{\frac{π}{2}} sec (x) d x

\int_{1}^{5} e^{- t} d t

\int_{x}^{1} y^{2} - 2 y + 1 d y

What is the integral from 0 to 5 of 1/(x^{0.5)} ?
The integral from 0 to 5 of 1/(x^{0.5)} is 2sqrt(5)