What is the integral from I(0) to I(t) of 1/I ?

The integral from I(0) to I(t) of 1/I is diverges

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integral from I(0) to I(t) of 1/I

\int_{I (0)}^{I (t)} \frac{1}{I} d I

diverges

Solution steps

\int_{I \cdot 0}^{I t} \frac{1}{I} d I

Use the common integral:

\int \frac{1}{I} d I = ln (∣ I ∣)

= [ln ∣ I ∣]_{0 \cdot I}^{t I}

Simplify

= [ln ∣ I ∣]_{0}^{t I}

Compute the boundaries:

diverges

= diverges

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What is the integral from I(0) to I(t) of 1/I ?
The integral from I(0) to I(t) of 1/I is diverges