What is the integral from 0 to 5 of 25cos(pi/(10)x) ?

The integral from 0 to 5 of 25cos(pi/(10)x) is (250)/pi

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integral from 0 to 5 of 25cos(pi/(10)x)

\int_{0}^{5} 25 cos (\frac{π}{10} x) d x

\frac{250}{π}

Decimal Notation

79.57747 \dots

Solution steps

\int_{0}^{5} 25 cos (\frac{π}{10} x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 25 \cdot \int_{0}^{5} cos (\frac{π}{10} x) d x

Multiply fractions:

a \cdot \frac{b}{c} = \frac{a \cdot b}{c}

= 25 \cdot \int_{0}^{5} cos (\frac{π x}{10}) d x

Apply u-substitution

: \int_{0}^{\frac{π}{2}} cos (u) \frac{10}{π} d u

= 25 \cdot \int_{0}^{\frac{π}{2}} cos (u) \frac{10}{π} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 25 \cdot \frac{10}{π} \cdot \int_{0}^{\frac{π}{2}} cos (u) d u

Use the common integral:

\int cos (u) d u = sin (u)

= 25 \cdot \frac{10}{π} [sin (u)]_{0}^{\frac{π}{2}}

Simplify

25 \cdot \frac{10}{π} [sin (u)]_{0}^{\frac{π}{2}} : \frac{250}{π} [sin (u)]_{0}^{\frac{π}{2}}

= \frac{250}{π} [sin (u)]_{0}^{\frac{π}{2}}

Compute the boundaries:

1

= \frac{250}{π} \cdot 1

Simplify

= \frac{250}{π}

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What is the integral from 0 to 5 of 25cos(pi/(10)x) ?
The integral from 0 to 5 of 25cos(pi/(10)x) is (250)/pi