What is the derivative of m/(2pi(a-x)) ?

The derivative of m/(2pi(a-x)) is m/(2pi(a-x)^2)

What is the first derivative of m/(2pi(a-x)) ?

The first derivative of m/(2pi(a-x)) is m/(2pi(a-x)^2)

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\frac{d}{d x} (\frac{m}{2 π ( a - x )})

\frac{m}{2 π ( a - x ) ^{2}}

Solution steps

\frac{d}{d x} (\frac{m}{2 π ( a - x )})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{m}{2 π} \frac{d}{d x} (\frac{1}{a - x})

Apply exponent rule:

\frac{1}{a} = a^{- 1}

= \frac{m}{2 π} \frac{d}{d x} ((a - x)^{- 1})

Apply the chain rule:

- \frac{1}{( a - x ) ^{2}} \frac{d}{d x} (a - x)

= - \frac{1}{( a - x ) ^{2}} \frac{d}{d x} (a - x)

\frac{d}{d x} (a - x) = - 1

= \frac{m}{2 π} (- \frac{1}{( a - x ) ^{2}} (- 1))

Simplify

\frac{m}{2 π} (- \frac{1}{( a - x ) ^{2}} (- 1)) : \frac{m}{2 π ( a - x ) ^{2}}

= \frac{m}{2 π ( a - x ) ^{2}}

\int_{0}^{2} \frac{7 t}{( t - 3 ) ^{2}} d t

\frac{d}{d x} (- 3 sin (x) - x cos (x))

\int_{0}^{\frac{π}{3}} 1

\frac{d}{d x} ((ln (x)) (ln (3 x - 7)))

f (x) = e^{- \frac{7}{x ^{7}}}

What is the derivative of m/(2pi(a-x)) ?
The derivative of m/(2pi(a-x)) is m/(2pi(a-x)^2)
What is the first derivative of m/(2pi(a-x)) ?
The first derivative of m/(2pi(a-x)) is m/(2pi(a-x)^2)