What is the integral from 0 to 2 of 1/(x^4) ?

The integral from 0 to 2 of 1/(x^4) is diverges

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integral from 0 to 2 of 1/(x^4)

\int_{0}^{2} \frac{1}{x ^{4}} d x

diverges

Solution steps

\int_{0}^{2} \frac{1}{x ^{4}} d x

Apply the Power Rule

: [- \frac{1}{3 x ^{3}}]_{0}^{2}

= [- \frac{1}{3 x ^{3}}]_{0}^{2}

Compute the boundaries:

diverges

= diverges

\int_{1}^{4} 5 x^{4} d x

\int_{0}^{1} (\frac{x + 5}{2})^{2} d x

\int_{1}^{3} x^{3} + x + 6 d x

\int_{0}^{π} cos (x) + 1 d x

\int_{0}^{2 π} \frac{1}{4} sin^{2} (x) d x

What is the integral from 0 to 2 of 1/(x^4) ?
The integral from 0 to 2 of 1/(x^4) is diverges