What is the integral from 1 to 7 of 6x^2+2x-3 ?

The integral from 1 to 7 of 6x^2+2x-3 is 714

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 7 of 6x^2+2x-3

\int_{1}^{7} 6 x^{2} + 2 x - 3 d x

714

Solution steps

\int_{1}^{7} 6 x^{2} + 2 x - 3 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{7} 6 x^{2} d x + \int_{1}^{7} 2 x d x - \int_{1}^{7} 3 d x

\int_{1}^{7} 6 x^{2} d x = 684

\int_{1}^{7} 2 x d x = 48

\int_{1}^{7} 3 d x = 18

= 684 + 48 - 18

Simplify

= 714

\int_{0}^{2} 1 - 0.5 x d x

\int_{0}^{3} \frac{- 2}{5 x + 1} d x

\int_{- 1}^{2} 4 t^{2} - 8 t + 5 d t

\int_{1}^{0} e^{x} d x

\int_{0}^{2 π} \frac{1}{5 - 4 cos ( x )} d x

What is the integral from 1 to 7 of 6x^2+2x-3 ?
The integral from 1 to 7 of 6x^2+2x-3 is 714