en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+y/x =0

Solution

y^{^{'}} + \frac{y}{x} = 0

Solution

y = \frac{c _{1}}{x}

Solution steps

y^{'} (x) + \frac{y}{x} = 0

Solve separable ODE:

y = \frac{c _{1}}{x}

y = \frac{c _{1}}{x}

Popular Examples

integral of (ln(x+1))/(sqrt(x+1))

\int \frac{ln ( x + 1 )}{x + 1} d x

integral from 0 to 1 of (x^3+1)/(x+1)

\int_{0}^{1} \frac{x ^{3} + 1}{x + 1} d x

derivative of ln(1/(1+e^{-x)})derivative of

ln (\frac{1}{1 + e ^{- x}})

derivative of 3xe^{-x}-2x

\frac{d}{d x} (3 x e^{- x} - 2 x)

derivative of (x+sqrt(1+x)/(x^2-1))

\frac{d}{d x} (\frac{x + 1 + x}{x ^{2} - 1})

Frequently Asked Questions (FAQ)

What is the solution for y^'+y/x =0 ?
The solution for y^'+y/x =0 is y=(c_{1})/x