What is the integral from 0 to 2 of (x^3+x^2+x) ?

The integral from 0 to 2 of (x^3+x^2+x) is 26/3

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integral from 0 to 2 of (x^3+x^2+x)

\int_{0}^{2} (x^{3} + x^{2} + x) d x

\frac{26}{3}

Decimal Notation

8.66666 \dots

Solution steps

\int_{0}^{2} x^{3} + x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{3} d x + \int_{0}^{2} x^{2} d x + \int_{0}^{2} x d x

\int_{0}^{2} x^{3} d x = 4

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} x d x = 2

= 4 + \frac{8}{3} + 2

Simplify

4 + \frac{8}{3} + 2 : \frac{26}{3}

= \frac{26}{3}

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What is the integral from 0 to 2 of (x^3+x^2+x) ?
The integral from 0 to 2 of (x^3+x^2+x) is 26/3