What is the integral from 0 to r of (r-(r^3)/(r^2)) ?

The integral from 0 to r of (r-(r^3)/(r^2)) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to r of (r-(r^3)/(r^2))

\int_{0}^{r} (r - \frac{r ^{3}}{r ^{2}}) d r

0

Solution steps

\int_{0}^{r} r - \frac{r ^{3}}{r ^{2}} d r

r - \frac{r ^{3}}{r ^{2}} = 0

= \int_{0}^{r} 0 d r

Integral of a constant:

\int a d x = a x

= [0 \cdot r]_{0}^{r}

Simplify

= [0]_{0}^{r}

Compute the boundaries:

0

= 0

\int_{0}^{π} sin^{3} (x) d x

\int_{- 1}^{2} 5 x^{2} d x

\int_{2}^{4} y^{2} d y

\int_{x^{2}}^{8 - x^{2}} y^{2} - x^{2} d y

\int_{\frac{π}{2}}^{π} (x - sin (x)) d x

What is the integral from 0 to r of (r-(r^3)/(r^2)) ?
The integral from 0 to r of (r-(r^3)/(r^2)) is 0