What is the integral from x to 2-x^2 of 1 ?

The integral from x to 2-x^2 of 1 is 2-x^2-x

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integral from x to 2-x^2 of 1

\int_{x}^{2 - x^{2}} 1 d y

2 - x^{2} - x

Solution steps

\int_{x}^{2 - x^{2}} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{x}^{2 - x^{2}}

Simplify

= [y]_{x}^{2 - x^{2}}

Compute the boundaries:

2 - x^{2} - x

= 2 - x^{2} - x

\int_{1}^{2} \frac{2 ^{l n (x)}}{x} d x

\int_{1}^{3} (8 x^{3} + 6 x - 45) d x

\int_{0}^{1} \frac{2 e ^{3 x}}{7} d x

\int_{0}^{a} (b cos (c x) + d) d x

\int_{2}^{3} \frac{1}{x ^{3} + 2 x} d x

What is the integral from x to 2-x^2 of 1 ?
The integral from x to 2-x^2 of 1 is 2-x^2-x