What is the integral from 0 to 1/2 of (2x^2+x) ?

The integral from 0 to 1/2 of (2x^2+x) is 5/24

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integral from 0 to 1/2 of (2x^2+x)

\int_{0}^{\frac{1}{2}} (2 x^{2} + x) d x

\frac{5}{24}

Decimal Notation

0.20833 \dots

Solution steps

\int_{0}^{\frac{1}{2}} 2 x^{2} + x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{1}{2}} 2 x^{2} d x + \int_{0}^{\frac{1}{2}} x d x

\int_{0}^{\frac{1}{2}} 2 x^{2} d x = \frac{1}{12}

\int_{0}^{\frac{1}{2}} x d x = \frac{1}{8}

= \frac{1}{12} + \frac{1}{8}

Simplify

\frac{1}{12} + \frac{1}{8} : \frac{5}{24}

= \frac{5}{24}

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What is the integral from 0 to 1/2 of (2x^2+x) ?
The integral from 0 to 1/2 of (2x^2+x) is 5/24