What is the integral from 0 to 27 of \sqrt[3]{x}-1/x ?

The integral from 0 to 27 of \sqrt[3]{x}-1/x is diverges

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integral from 0 to 27 of \sqrt[3]{x}-1/x

diverges

Solution steps

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

\int_{0}^{27} \frac{1}{x} d x =

diverges

If part of the expression diverges, then entire expression diverges

= diverges

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What is the integral from 0 to 27 of \sqrt[3]{x}-1/x ?
The integral from 0 to 27 of \sqrt[3]{x}-1/x is diverges