What is the integral from-6 to-3 of 2x^2+16x+34 ?

The integral from-6 to-3 of 2x^2+16x+34 is 12

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integral from-6 to-3 of 2x^2+16x+34

\int_{- 6}^{- 3} 2 x^{2} + 16 x + 34 d x

12

Solution steps

\int_{- 6}^{- 3} 2 x^{2} + 16 x + 34 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 6}^{- 3} 2 x^{2} d x + \int_{- 6}^{- 3} 16 x d x + \int_{- 6}^{- 3} 34 d x

\int_{- 6}^{- 3} 2 x^{2} d x = 126

\int_{- 6}^{- 3} 16 x d x = - 216

\int_{- 6}^{- 3} 34 d x = 102

= 126 - 216 + 102

Simplify

= 12

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What is the integral from-6 to-3 of 2x^2+16x+34 ?
The integral from-6 to-3 of 2x^2+16x+34 is 12