What is the integral from 0 to pi/4 of sec^2(y) ?

The integral from 0 to pi/4 of sec^2(y) is 1

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integral from 0 to pi/4 of sec^2(y)

\int_{0}^{\frac{π}{4}} sec^{2} (y) d y

1

Solution steps

\int_{0}^{\frac{π}{4}} sec^{2} (y) d y

Use the common integral:

\int sec^{2} (y) d y = tan (y)

= [tan (y)]_{0}^{\frac{π}{4}}

Compute the boundaries:

1

= 1

\int_{0}^{2} (k x + 1) d x

\int_{0}^{3} x^{3} + 2 d x

\int_{0}^{3} 1 + 9 - x^{2} d x

\int_{2}^{x} (x^{2} + 3 x - 5) d x

\int_{0}^{8} 3 x^{2} - 36 x + 105 d x

What is the integral from 0 to pi/4 of sec^2(y) ?
The integral from 0 to pi/4 of sec^2(y) is 1