What is the integral from 0 to pi/6 of cos(3A) ?

The integral from 0 to pi/6 of cos(3A) is pi/6 cos(3A)

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integral from 0 to pi/6 of cos(3A)

\int_{0}^{\frac{π}{6}} cos (3 A)

\frac{π}{6} cos (3 A)

Solution steps

\int_{0}^{\frac{π}{6}} cos (3 A) d x

Integral of a constant:

\int a d x = a x

= [cos (3 A) x]_{0}^{\frac{π}{6}}

Compute the boundaries:

\frac{π}{6} cos (3 A)

= \frac{π}{6} cos (3 A)

\int_{0}^{1} 2 x^{2} - x^{3} d x

\int_{y - 1}^{1 - y} x d x

\int_{0}^{4} \frac{2 t}{t ^{2} - 25} d t

\int_{\frac{π}{4}}^{\frac{π}{2}} 2 - cot^{2} (x) d x

\int_{0}^{1} 4 x^{3} x^{2} + 1 d x

What is the integral from 0 to pi/6 of cos(3A) ?
The integral from 0 to pi/6 of cos(3A) is pi/6 cos(3A)