What is the integral from-pi/2 to pi/2 of sin(2t) ?

The integral from-pi/2 to pi/2 of sin(2t) is 0

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integral from-pi/2 to pi/2 of sin(2t)

\int_{- \frac{π}{2}}^{\frac{π}{2}} sin (2 t) d t

0

Solution steps

\int_{- \frac{π}{2}}^{\frac{π}{2}} sin (2 t) d t

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

sin (2 t) :

Odd

= 0

\int_{- 2}^{3} y^{2} - y - 6 d y

\int_{0}^{2} 4 t^{2} + 9 t^{4} d t

\int_{2}^{5} (ln (x))^{2} d x

\int_{0}^{\infty} A e^{- λ t} d t

\int_{0}^{t} e^{- 3 u} d u

What is the integral from-pi/2 to pi/2 of sin(2t) ?
The integral from-pi/2 to pi/2 of sin(2t) is 0