What is the integral from 0 to 2sqrt(1-y^2 of)y ?

The integral from 0 to 2sqrt(1-y^2 of)y is 2(-y^2+1)

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integral from 0 to 2sqrt(1-y^2 of)y

\int_{0}^{2 1 - y^{2}} y d y

2 (- y^{2} + 1)

Solution steps

\int_{0}^{2 1 - y^{2}} y d y

Apply the Power Rule

: [\frac{y ^{2}}{2}]_{0}^{2 1 - y^{2}}

= [\frac{y ^{2}}{2}]_{0}^{2 1 - y^{2}}

Compute the boundaries:

2 (- y^{2} + 1)

= 2 (- y^{2} + 1)

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What is the integral from 0 to 2sqrt(1-y^2 of)y ?
The integral from 0 to 2sqrt(1-y^2 of)y is 2(-y^2+1)