What is the integral from 0 to pi/3 of sin^2(θ) ?

The integral from 0 to pi/3 of sin^2(θ) is (4pi-3sqrt(3))/(24)

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integral from 0 to pi/3 of sin^2(θ)

\int_{0}^{\frac{π}{3}} sin^{2} (θ) d θ

\frac{4 π - 3 3}{24}

Decimal Notation

0.30709 \dots

Solution steps

\int_{0}^{\frac{π}{3}} sin^{2} (θ) d θ

Rewrite using trig identities

= \int_{0}^{\frac{π}{3}} \frac{1 - cos ( 2 θ )}{2} d θ

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{2} \cdot \int_{0}^{\frac{π}{3}} 1 - cos (2 θ) d θ

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \frac{1}{2} (\int_{0}^{\frac{π}{3}} 1 d θ - \int_{0}^{\frac{π}{3}} cos (2 θ) d θ)

\int_{0}^{\frac{π}{3}} 1 d θ = \frac{π}{3}

\int_{0}^{\frac{π}{3}} cos (2 θ) d θ = \frac{3}{4}

= \frac{1}{2} (\frac{π}{3} - \frac{3}{4})

Simplify

\frac{1}{2} (\frac{π}{3} - \frac{3}{4}) : \frac{4 π - 3 3}{24}

= \frac{4 π - 3 3}{24}

\int_{0}^{3 π} 2 cos^{2} (\frac{x}{3}) d x

\int_{0}^{4} cosh (x) d x

\int_{0}^{\infty} e^{- \frac{1}{5}}

\int_{- 1}^{1} 4 (1 - x^{2}) - (1 - x^{2}) d x

\int_{1}^{2} x^{2} - x + 3 d x

What is the integral from 0 to pi/3 of sin^2(θ) ?
The integral from 0 to pi/3 of sin^2(θ) is (4pi-3sqrt(3))/(24)