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Popular >

integral from-1 to 2 of (y^2+2)

Solution

\int_{- 1}^{2} (y^{2} + 2) d y

Solution

9

Solution steps

\int_{- 1}^{2} y^{2} + 2 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} y^{2} d y + \int_{- 1}^{2} 2 d y

\int_{- 1}^{2} y^{2} d y = 3

\int_{- 1}^{2} 2 d y = 6

= 3 + 6

Simplify

= 9

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\int_{1}^{\infty} \frac{1}{x + 6} d x

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\int_{3}^{5} 8 + x^{2} d x

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\int_{0}^{\frac{π}{2}} cos (0 x) d x

Frequently Asked Questions (FAQ)

What is the integral from-1 to 2 of (y^2+2) ?
The integral from-1 to 2 of (y^2+2) is 9