What is the integral from 0 to sqrt(x of)1 ?

The integral from 0 to sqrt(x of)1 is sqrt(x)

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integral from 0 to sqrt(x of)1

\int_{0}^{x} 1 d y

x

Solution steps

\int_{0}^{x} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{0}^{x}

Simplify

= [y]_{0}^{x}

Compute the boundaries:

x

= x

\int_{- 1}^{2} (\frac{4}{3} x^{3} + 4 x^{2} + x) d x

\int_{0}^{5} x (\frac{2 x}{25}) d x

\int_{0}^{4} e^{- 3 t} d t

\int_{0}^{18} x (\frac{1}{162} x) d x

\int_{0}^{2} 3 x^{2} - 2 x d x

What is the integral from 0 to sqrt(x of)1 ?
The integral from 0 to sqrt(x of)1 is sqrt(x)