What is the integral from 0 to pi/2 of 3-3sin(x) ?

The integral from 0 to pi/2 of 3-3sin(x) is (3pi)/2-3

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integral from 0 to pi/2 of 3-3sin(x)

\int_{0}^{\frac{π}{2}} 3 - 3 sin (x) d x

\frac{3 π}{2} - 3

Decimal Notation

1.71238 \dots

Solution steps

\int_{0}^{\frac{π}{2}} 3 - 3 sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{\frac{π}{2}} 3 d x - \int_{0}^{\frac{π}{2}} 3 sin (x) d x

\int_{0}^{\frac{π}{2}} 3 d x = \frac{3 π}{2}

\int_{0}^{\frac{π}{2}} 3 sin (x) d x = 3

= \frac{3 π}{2} - 3

\int_{- 2}^{2} e^{- x} d x

\int_{1}^{1} 1 - z d z

\int_{0}^{4} \frac{x ^{2} - 1}{x ^{2} + 2} d x

\int_{1}^{\infty} \frac{1}{2 n + 1}

\int_{π}^{π} cos (x) d x

What is the integral from 0 to pi/2 of 3-3sin(x) ?
The integral from 0 to pi/2 of 3-3sin(x) is (3pi)/2-3