What is the integral from-1 to 3 of x^{2/3}+1 ?

The integral from-1 to 3 of x^{2/3}+1 is (9*3^{2/3}+3)/5+4

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integral from-1 to 3 of x^{2/3}+1

\int_{- 1}^{3} x^{\frac{2}{3}} + 1 d x

\frac{9 \cdot 3 ^{\frac{2}{3}} + 3}{5} + 4

Decimal Notation

8.34415 \dots

Solution steps

\int_{- 1}^{3} x^{\frac{2}{3}} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{3} x^{\frac{2}{3}} d x + \int_{- 1}^{3} 1 d x

\int_{- 1}^{3} x^{\frac{2}{3}} d x = \frac{9 \cdot 3 ^{\frac{2}{3}} + 3}{5}

\int_{- 1}^{3} 1 d x = 4

= \frac{9 \cdot 3 ^{\frac{2}{3}} + 3}{5} + 4

\int_{1}^{2} \frac{1}{( x - 1 ) ( 2 - x )} d x

\int_{1}^{3} \frac{3 x - y}{9} d x

\int_{0}^{\frac{π}{2}} 4 d x

\int_{1}^{5} \frac{ln ( x ^{2} )}{x ^{3}} d x

\int_{1}^{2} \frac{ln ( x )}{x ^{6}} d x

What is the integral from-1 to 3 of x^{2/3}+1 ?
The integral from-1 to 3 of x^{2/3}+1 is (9*3^{2/3}+3)/5+4