What is the integral of (sin(x))/(cos^4(x)) ?

The integral of (sin(x))/(cos^4(x)) is 1/3 sec^3(x)+C

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integral of (sin(x))/(cos^4(x))

\int \frac{sin ( x )}{cos ^{4} ( x )} d x

\frac{1}{3} sec^{3} (x) + C

Solution steps

\int \frac{sin ( x )}{cos ^{4} ( x )} d x

Rewrite using trig identities

= \int \frac{tan ( x )}{cos ^{3} ( x )} d x

Use the basic trigonometric identity:

\frac{1}{cos ( x )} = sec (x)

= \int sec^{3} (x) tan (x) d x

Apply u-substitution

: \int \frac{1}{3} d u

= \int \frac{1}{3} d u

Integral of a constant:

\int a d x = a x

= \frac{1}{3} u

Substitute back

u = sec^{3} (x)

= \frac{1}{3} sec^{3} (x)

Add a constant to the solution

= \frac{1}{3} sec^{3} (x) + C

\frac{5 x}{( 1 + x ^{2} )}

2 x^{3} + 3 x^{2} - 12 x + 4

\frac{\partial}{\partial x} (x^{2} \cdot y + \frac{x e ^{x}}{y ^{3}})

\int \frac{1}{3 + 2 x ^{2}} d x

\int (2) d x

What is the integral of (sin(x))/(cos^4(x)) ?
The integral of (sin(x))/(cos^4(x)) is 1/3 sec^3(x)+C