What is the integral from-pi to 0 of 1/pi ?

The integral from-pi to 0 of 1/pi is 1

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integral from-pi to 0 of 1/pi

\int_{- π}^{0} \frac{1}{π}

1

Solution steps

\int_{- π}^{0} \frac{1}{π} d x

Integral of a constant:

\int a d x = a x

= [\frac{1}{π} x]_{- π}^{0}

Compute the boundaries:

1

= 1

\int_{- 2}^{2} 5 t^{4} d t

\int_{0}^{1} (1 - x^{2}) cos (nπ x) d x

\int_{0}^{2} 1 + (2 - 2 x)^{2} d x

\int_{0}^{π} (3 + cos (x)) d x

\int_{3}^{8} 2 x^{2} ln (x - 2) d x

What is the integral from-pi to 0 of 1/pi ?
The integral from-pi to 0 of 1/pi is 1