What is the integral from 0 to x of sec^2(x) ?

The integral from 0 to x of sec^2(x) is tan(x)

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integral from 0 to x of sec^2(x)

\int_{0}^{x} sec^{2} (x) d x

tan (x)

Solution steps

\int_{0}^{x} sec^{2} (x) d x

Use the common integral:

\int sec^{2} (x) d x = tan (x)

= [tan (x)]_{0}^{x}

Compute the boundaries:

tan (x)

= tan (x)

\int_{\frac{y ^{2}}{40}}^{20} (40 + x) d x

\int_{0}^{x} e^{- 2 t^{2}} d t

\int_{0}^{2} 5 x^{2} + 1 d x

\int_{4}^{5} \frac{1}{( x - 4 ) ^{\frac{1}{3}}} d x

\int_{0}^{3} t 4 + 9 t^{2} d t

What is the integral from 0 to x of sec^2(x) ?
The integral from 0 to x of sec^2(x) is tan(x)