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Popular >

integral from 1 to 5 of (x^2+1)

Solution

\int_{1}^{5} (x^{2} + 1) d x

Solution

\frac{136}{3}

+1

Decimal Notation

45.33333 \dots

Solution steps

\int_{1}^{5} x^{2} + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} x^{2} d x + \int_{1}^{5} 1 d x

\int_{1}^{5} x^{2} d x = \frac{124}{3}

\int_{1}^{5} 1 d x = 4

= \frac{124}{3} + 4

Simplify

\frac{124}{3} + 4 : \frac{136}{3}

= \frac{136}{3}

Popular Examples

integral from-1 to 3 of x^3-3x^2-1

\int_{- 1}^{3} x^{3} - 3 x^{2} - 1 d x

integral from 0 to 2 of x/(4sqrt(4-x^2))

\int_{0}^{2} \frac{x}{4 4 - x ^{2}} d x

integral from 0 to 1 of 3k-kx

\int_{0}^{1} 3 k - k x d x

integral from-4 to 4 of y/(sqrt(16-y^2))

\int_{- 4}^{4} \frac{y}{16 - y ^{2}} d y

integral from-1 to 2 of (3x^2-2)

\int_{- 1}^{2} (3 x^{2} - 2) d x

Frequently Asked Questions (FAQ)

What is the integral from 1 to 5 of (x^2+1) ?
The integral from 1 to 5 of (x^2+1) is 136/3