What is the integral from 0 to pi of (3+sin(x)) ?

The integral from 0 to pi of (3+sin(x)) is 3pi+2

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integral from 0 to pi of (3+sin(x))

\int_{0}^{π} (3 + sin (x)) d x

3 π + 2

Decimal Notation

11.42477 \dots

Solution steps

\int_{0}^{π} 3 + sin (x) d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{π} 3 d x + \int_{0}^{π} sin (x) d x

\int_{0}^{π} 3 d x = 3 π

\int_{0}^{π} sin (x) d x = 2

= 3 π + 2

\int_{0}^{- 1} x d x

\int_{1}^{2} ((2 - t) t) d t

\int_{2}^{4} 2^{x} d x

\int_{0}^{3} 1 + 1296 x^{2} d x

\int_{2}^{3} 3 sin (\frac{π}{3} x) d x

What is the integral from 0 to pi of (3+sin(x)) ?
The integral from 0 to pi of (3+sin(x)) is 3pi+2