What is the integral from 0.2 to 0.8 of 2x ?

The integral from 0.2 to 0.8 of 2x is 0.6

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integral from 0.2 to 0.8 of 2x

\int_{0.2}^{0.8} 2 x d x

0.6

Solution steps

\int_{0.2}^{0.8} 2 x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0.2}^{0.8} x d x

Apply the Power Rule

= 2 [\frac{x ^{2}}{2}]_{0.2}^{0.8}

Simplify

= 2 [0.5 x^{2}]_{0.2}^{0.8}

Compute the boundaries:

0.3

= 2 \cdot 0.3

Simplify

= 0.6

\int_{1}^{2} \frac{1}{x ( ln ( x ) )} d x

\int_{1}^{π} ln (t) d t

\int_{0}^{18} x^{2} d x

\int_{1}^{1} x ln (x) d x

\int_{0}^{1} 2 x x + 1 d x

What is the integral from 0.2 to 0.8 of 2x ?
The integral from 0.2 to 0.8 of 2x is 0.6