What is the integral from 0 to 0.5 of 2x^2 ?

The integral from 0 to 0.5 of 2x^2 is 0.08333…

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 0 to 0.5 of 2x^2

\int_{0}^{0.5} 2 x^{2} d x

0.08333 \dots

Solution steps

\int_{0}^{0.5} 2 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{0.5} x^{2} d x

Apply the Power Rule

= 2 [\frac{x ^{3}}{3}]_{0}^{0.5}

Simplify

= 2 [0.33333 \dots x^{3}]_{0}^{0.5}

Compute the boundaries:

0.04166 \dots

= 2 \cdot 0.04166 \dots

Simplify

= 0.08333 \dots

\int_{1}^{5} (\frac{10}{x ^{2}})^{2} d x

\int_{0}^{2} π (x^{2} + 2)^{2} d x

\int_{1}^{\frac{3}{2}} (2 - x - \frac{1}{3} x) d x

\int_{0}^{2} \frac{x}{x + 2} d x

\int_{- 2}^{3} (5 x^{2} - 3 x) d x

What is the integral from 0 to 0.5 of 2x^2 ?
The integral from 0 to 0.5 of 2x^2 is 0.08333…