What is the integral from 0 to 4 of sqrt(x)+1 ?

The integral from 0 to 4 of sqrt(x)+1 is 28/3

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integral from 0 to 4 of sqrt(x)+1

\int_{0}^{4} x + 1 d x

\frac{28}{3}

Decimal Notation

9.33333 \dots

Solution steps

\int_{0}^{4} x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} x d x + \int_{0}^{4} 1 d x

\int_{0}^{4} x d x = \frac{16}{3}

\int_{0}^{4} 1 d x = 4

= \frac{16}{3} + 4

Simplify

\frac{16}{3} + 4 : \frac{28}{3}

= \frac{28}{3}

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What is the integral from 0 to 4 of sqrt(x)+1 ?
The integral from 0 to 4 of sqrt(x)+1 is 28/3