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Popular >

integral from 0 to 2 of (ti-t^3j+3t^5k)

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Solution

∫02​(ti−t3j+3t5k)dt

Solution

i2−j⋅4+32k
Solution steps
∫02​ti−t3j+3t5kdt
Apply the Sum Rule: ∫f(x)±g(x)dx=∫f(x)dx±∫g(x)dx=∫02​tidt−∫02​t3jdt+∫02​3t5kdt
∫02​tidt=i2
∫02​t3jdt=j⋅4
∫02​3t5kdt=32k
=i2−j⋅4+32k

Popular Examples

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Frequently Asked Questions (FAQ)

  • What is the integral from 0 to 2 of (ti-t^3j+3t^5k) ?

    The integral from 0 to 2 of (ti-t^3j+3t^5k) is i2-j*4+32k
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