What is the integral from 1 to 4 of (x^3) ?

The integral from 1 to 4 of (x^3) is 255/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

integral from 1 to 4 of (x^3)

\int_{1}^{4} (x^{3}) d x

\frac{255}{4}

Decimal Notation

63.75

Solution steps

\int_{1}^{4} x^{3} d x

Apply the Power Rule

: [\frac{x ^{4}}{4}]_{1}^{4}

= [\frac{x ^{4}}{4}]_{1}^{4}

Compute the boundaries:

\frac{255}{4}

= \frac{255}{4}

\int_{\frac{x}{2}}^{x} - sin (x) d x

\int_{1}^{2} \frac{4 x ^{2} - 3 x + 4}{x} d x

\int_{0}^{4} π (16 - x^{2})^{2} d x

\int_{- 1}^{3} (6 x y - 5 y) d y

\int_{0}^{1} \frac{x ^{3}}{x ^{2} + 6 x + 9} d x

What is the integral from 1 to 4 of (x^3) ?
The integral from 1 to 4 of (x^3) is 255/4